lambda - Extending List<T> in Java 8 -

i want map 1 list list. example if had list of people, , wanted list of names, do:

goal

list<person> people = ... ;  list<string> names = people.map(x -> x.getname());

something possible java 8:

java 8 version

list<string> names = people.stream()                            .map(x -> x.getname())                            .collect(collectors.tolist());

but not nice. in fact, think using guava cleaner:

guava version

list<string> names = lists.transform(people, x -> x.getname());

however, chaining. so, goal possible?

i have heard people java 8 default methods similar c# extension methods. c# extension method, add helper method ienumerable<t>:

public static ienumerable<tret> map<t, tret>(this ienumerable<t> list, func<t, tret> selector) {     return list.select(selector); }

however can't figure out how use default methods extend existing interface.

also, trivial example. in general, able extend list<t> , iterable<t> interfaces make interacting streams api easier.

no; can't that.

default methods not same extension methods; can defined within original interface.

And