xslt - getting all child nodes of element -


i have xml file on applying transformation specific element , try text() of child nodes ignoring same node 

<xml>     <xrefline>               <query>eligible individual</query>               in respect of qualified dependant @ time means person @ time                  <quote>               <para>                 <n>(a)</n>                <parap>resides qualified dependant,</parap>              </para>                </quote>        </xrefline>      </xml>

my xslt template looks , want extract text() , preserve query element

<xsl:template match="query" > <xsl:apply-templates select="../text()|../node()[self::query]|../node()[not(self::query)]/text()" ></xsl:apply-templates> </xsl:template>

my desire output should 

     <xml>          <xrefline>               <query>eligible individual</query>               in respect of qualified dependant @ time means person @ time (a) resides qualified dependant,          </xrefline>      </xml>

i have work around template match="query" , go desire result. above xslt getting text out side element quote not text of sub childs of quote element... or hint helpful.

i write 2 templates:

<xsl:template match="@* | node()">   <xsl:copy>     <xsl:apply-templates select="@* , node()"/>   </xsl:copy> </xsl:template>  <xsl:template match="xrefline//*[not(self::query)]">   <xsl:apply-templates/> </xsl:template>

see http://xsltransform.net/948fn5h.


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