c++ - Template: get proper variable name from type name -

let's say, have 4 arrays of 4 different pointer types. , want template function, stores it's argument in proper array. this

int*            arr_int[10]; double*         arr_double[10]; uint64_t*       arr_uint64_t[10];   template <typename t>  void add_value (int pos, t value) {         //i want store value in array of it's type         arr_##(*t)[pos]=value;         //of course, not work :) }  int main(int argc, char *argv[]) {         int      = 2;         double   b = 4.2;         uint64_t c = 123456;          add_value(0,&a);         add_value(0,&b);         add_value(0,&c);          //add more values         //do arrays         ....          return 0; }  

is possible?

no, name generation not possible via templates in way mean it. can nick said - create overloaded functions, or create template class static array of specified type:

template <typename t> struct array_holder {     static t * arr[10]; };  template <typename t> t * array_holder<t>::arr[10];  template <typename t> void add_value (int pos, t value) {     array_holder<t>::arr[pos] = something_you_need; }