mysql - How to distinct sum() when using joins -


i have 2 tables. 1 holds data ok parts , other rejects.

i receive data in following format:

| yyyy-mm | sum(ok.qty) | sum(reject.qty) | reject % |

1) possible use join , kind of distinct sum(ok.qty)?

select      date_format(date, '%y-%m'),      sum(ok.qty),      sum(reject.qty),      sum(reject.qty) / sum(reject.qty + ok.qty) reject_percent ok join reject on ok.id = reject.ok_id group date_format(date, '%y-%m')

2) if not how eliminate duplicate sub-queries?

select      date_format(date, '%y-%m'),      sum(ok.qty),      (select qty reject ok_id = ok.id),      (select qty reject ok_id = ok.id) /          ( (select qty reject ok_id = ok.id) + sum(ok.qty) )          reject_percent ok group date_format(date, '%y-%m')

right had write 1 query 3 times.

database design:

ok.id can have mutiple rejects.

database

you can try this..

select      date_format(date, '%y-%m'),      sum(ok.qty),      sum(reject.qty),      ((sum(reject.qty) / sum(reject.qty + ok.qty))*100)as reject_percent ok inner join (select ok_id,sum(qty) qty reject group ok_id) reject on ok.id = reject.ok_id group date_format(date, '%y-%m')

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