PHP - Count array based on other array -

i have array

$array1 = array(array('b','d'),                  array('c','a'),                 array('b','d'),                 array('a','d'),                 array('c'),                 array('c'),                 array('a','d','e'),                 array('d','b')                  );  $array2 = array(array('c'),array('a','d'), array('b','d'), array('a,','d','e')) ; $result = array(); 

here's code:

    foreach ($array2 $part) {         $key = implode(', ', $part);         if( ! array_key_exists ($key, $array1)) {             $result[$key] = 0;         }         $result[$key] = $result[$key] + 1;     }     foreach ($result $key => $value) {         echo "$value of {$key}<br/>";        } 

i want count values $array2 based on $array1
got one:

1 of c       1 of a, d 1 of b, d   1 of a, d, e 

but want result this:

3 of c       2 of a, d 2 of b, d   1 of a, d, e   

if wonders why there's (2 of a,d), array('a','d') , array('a','d','e')

this code should work:

$result = array(); $array1 = array(     array('b','d'),      array('c','a'),     array('b','d'),     array('a','d'),     array('c'),     array('c'),     array('a','d','e'),     array('d','b') ); $array2 = array(     array('c'),     array('a','d'),     array('b','d'),     array('a,','d','e') );  foreach ($array2 $part) {     $key = implode(', ', $part);     if(!array_key_exists ($key, $array1)) {         $result[$key] = 0;     }     foreach($array1 $data) {         $datakey = implode(', ', $data);         if(strpos($datakey, $key) > -1) {             $result[$key]++;         }     }  } foreach ($result $key => $value) {     echo "$value of {$key}<br/>";    } 

the result produces is:

3 of c 2 of a, d 2 of b, d 0 of a,, d, e 

notice 0 of a,, d, e. caused typo in $array2 - array('a,','d','e')