django - Using modelForm hidden field with Formsets without using Crispyform. -


i working forms sets, wondering how 1 use

<input type='hidden'

inside form set. (django formsets allow use multiple forms instances of single form)

its easy in normal single form put field type='hidden' , name='fieldname' e.g.

<input type='hidden' name='user' value='{{request.user.id}}'>

dealing formsets bit catchy, how achieve same behavior forms sets?

views.py

pictureformset = modelformset_factory(picture, form=updatepictureform, extra=0)     formset_qset = picture.objects.filter(id__in=[15, 16, 17, 18, 19, 20])     if request.method == post:         ctx['form_set'] = pictureformset(request.post, queryset=formset_qset)         ctx['form_set'].save()      ctx['form_set'] = pictureformset(queryset=formset_qset)      return render_to_response('temp tabs.html', context_instance=requestcontext(request, ctx)) 

template

 <form method="post" action="" class="form-horizontal">                  {% form in form_set %}                     {{form.id}}                     <div class="form-group">                         <label class="col-lg-2 control-label">                             {% form.meta_data.value|load_meta_data meta %}                                 <div class="portfolio-item video-container">                                     <a class="" href="{% url 'view_image' form.id.value %}?in=pro">                                         <i style="background-image: url({{ meta.image_size.thumbnail_small }});"                                            class="ds-thumbnail-container"></i>                                     </a>                                 </div>                             {% endwith %}                         </label>                          <div class="col-lg-8 ">                              {{ form.name }}                            </div>                     </div>                  {% endfor %}                 {{ form_set.management_form }}              {% csrf_token %}             <input type="submit" value="submit">             </form> 

explanation

here in code, rendering images database editing there names. have url information inside meta_data, have selected

fields=['id', 'meta_data', 'name'] 

we want change/update name, not meta_data

this code works fine part, how want keep 1 field unchanged modal?

i have meta_data field using in template, not want field modified, value should in form this

{{form.meta_data}} turns text area, different name , id. , expects changing. want declare hidden field , sets value form.meta_data.value

if have questions regarding please not hesitate ask. thanks.


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