How to integrate my own app in elgg -


i create new widget(quiz) in elgg can put own content. have there default menus, etc. empty space can put code.

the user should able view quiz based on login. should done new plugin? if yes, how create empty page current template settings?


Comments

Post a Comment

Popular posts from this blog

google app engine - 403 Forbidden POST - Flask WTForms -

i have flask application running on google app engine. trying submit form built using wtform , keep getting following error. 403 forbidden: don't have permission access requested resource. either read-protected or not readable server. location.html (part of code) <form method=post action="/home/location"> .... <button type="submit" class="btn btn-primary" value="submit"> directions </button> </form> main.py @app.route('/home/location', methods=['post', 'get']) def location(): form = cfcdirections.direction(request.form) print(request.method) if request.method == 'post' , form.validate(): print("after if") directions = cfcdirections() street_no = directions.no street = directions.street suburb = directions.suburb postcode = directions.postcode ...
Read more

ruby on rails - In a controller spec, how to find a specific tag in the generated view? -

i know integration tests preferred need ran in controller test, i'm testing gem injecting html code in view, xhr can't run in feature spec (if can, please explain me how :) ) so rspec controller tests can assert selector present (with capybara) : response.body.should have_selector('#foobar') has_selector? call all method capybara find selector. what want last child of body , assert id in particular. afaik it's not possible have_selector. what : all('body:first-child').first.id.should == '#foobar' however, capybara dsl, defined (more or less): def all(*args) page.all(*args) end and page empty unless use visit it's integrations specs. how can use capybara all method inside rspec controller test ? i can't test right after googling seems trick def page capybara::node::simple.new(response.body) end source
Read more

how to run a query SQL in node.js mysql -

i have syntax problem in module, fail sql query. i initialize module database in file.js, responds console.log 'connected database', sends data module in database.newdata(data), when enters in runquery nothing happens, no errors or result, nothing! i in runquery if query ok , if this, think happens there error in logic of node, idea connect database , use runquery run query pass. file.js var db = require('./modules/database'); var database = new db(); database.newdata(data); database.js var mysql = require('mysql'), queries = require('./queries'), connection; var db = function(){ var db_config = { host: 'localhost', user: 'diegoug', password: 'qwertyuiop', database: 'test' }; connection = mysql.createconnection(db_config); connection.connect(function(err) { if(err) { console.log('error when connecting database:', err); ...
Read more