regex + Python: How to find string with '?' in it? -


i have multi-line string in content variable, , need retreive matches pattern uri containing question mark in it.

this have far:

content = """ /blog:text:lorem ipsum dolor sit amet, consectetur adipisicing elit <break> text:duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore <break> text:excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia.  /blog?page=1:text:lorem ipsum dolor sit amet, consectetur adipisicing elit <break> text:duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore <break> text:excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia. """  #uri = '/blog' # works fine uri = '/blog?page=1' re.findall('^(?ism)%s?:(.*?)(\n\n)' % uri, content)

it works fine until uri gets ? parameters after it, , empty list.

any ideas how fix regex?

python's re.escape() friend. if don't use it, ? inside uri treated usual meaning inside of regular expression (making prior item 0-or-1 match).

uri = '/blog?page=1' re.findall('^(?ism)%s?:(.*?)(\n\n)' % re.escape(uri), content)

i'm not clear want ?: after the %s do, i'm leaving in on potentially-faulty presumption it's there reason.


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