php - using in_array return next array if the in_array is empty -

i have array

$array = array(     array('a', '18:27:15', 'label1'),     array('b', '18:27:20', 'label2'),     array('c', '18:27:25', 'label3'),     array('d', '18:27:30', 'label4'),     array('e', '18:27:35', 'label5'),     array('f', '18:27:40', 'label6'),     array('g', '18:27:45', 'label7'),     array('h', '18:27:50', 'label8') ); 

im checking see whether have time string in array,for example if give

 $end_time="18:27:25";   

i array result , if give

$end_time="18:27:26"; 

i empty array. need return next array instead

array('d','18:27:30','label4') 

below code

$arr_output = array(); foreach ($array $key=>$arr1){     if( in_array($end_time, $arr1) ){         $arr_output[$key]=$arr1;     } } print_r(arr_output);//empty 

you convert them timestamps , compare:

$result = null; $target = strtotime('18:27:41');  foreach ($array $item) {     $compare = strtotime($item[1]);      if ($compare >= $target) {         if (null === $result) {             $result = $item;         } else if($target - strtotime($result[1]) < $target - $compare) {             $result = $item;         }     } }  echo print_r($result, 1); 

with approach, :20 point 18:27:20, , :21 point 18:27:25.

note approach not need original array in particular order, each item considered.