mysql - Undefined variable error in PHP, code-logic - 


$res = $mysqli->query("select anhid anhoriga pnr='".$_post['pnr2']."'"); while($row = $res->fetch_assoc()){    $anhid = array_shift($row); }  $res = $mysqli->query("insert samband2 values(".$anhid.", ".$_post['pnr'].")");

this code gets me error line:

>notice: undefined variable: anhid in c:\xampp\htdocs\skapa.php on line 18.

the last row of code line 18.

am stupid, or didn't define variable $anhid in previous code???! in specifics, i'm creating employee register, connected database containing info them.

$anhid in return variable(and primary key in database) contains unique id each of acquaintances employees.

$_post['pnr2'] contains social security number of acquaintance.

anhoriga table , spelled correctly.

please can explain i've done wrong?

declare anhid .  looks sql not returning data. thats why anhid not getting set.  var  $anhid =""; $res = $mysqli->query("select anhid anhoriga pnr='".$_post['pnr2']."'");     while($row = $res->fetch_assoc()){         $anhid = array_shift($row);     }  if(!empty($anhid)){   $res = $mysqli->query("insert samband2 values(".$anhid.", ".$_post['pnr'].")"); }

if think there multiple anhid should put insert inside while loop or if select returns 1 row , dont need while loop.


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